Posted by: dev P June 21, 2016
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Its easy bro, output is 1. Its because you have passed 1 as argument in closure, 'x' will have value 1. As in Javacript inner function has access to its parent function variables, so value of x inside inner function will stay 1. Its easy(not tricky) because variable value has not been overidden as you are using 'y' as argument in inner function.