Posted by: lootekukur August 25, 2008
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sumitt,
what i meant was:
the first 3 hints given by tinkune is enough to solve this problem. we don't need to know there is a twin.
and here's why:
if you take all combinations of three digits whose product is 72, of all such combinations, only two has one sum (14): 6 6 2 and 8 3 3.
other produce unique sums:
(1*1*72) = 75 sum
(1*2*36)=39 sum
(1*3*24)=28 sum
(1*4*18)=23 sum
(1*6*12)=19 sum
(1*8*9)=18 sum
so on and so forth.
If the house no. was one of those unique sums; the first two hints would have sufficed. but since it was 14 (which has two possibilities), he needed the third hint.
what i meant was:
the first 3 hints given by tinkune is enough to solve this problem. we don't need to know there is a twin.
and here's why:
if you take all combinations of three digits whose product is 72, of all such combinations, only two has one sum (14): 6 6 2 and 8 3 3.
other produce unique sums:
(1*1*72) = 75 sum
(1*2*36)=39 sum
(1*3*24)=28 sum
(1*4*18)=23 sum
(1*6*12)=19 sum
(1*8*9)=18 sum
so on and so forth.
If the house no. was one of those unique sums; the first two hints would have sufficed. but since it was 14 (which has two possibilities), he needed the third hint.