HI Yekloyatri here is your solution for 1 A'B +AB' + AB + A'B' = 1 rearrange them first A'B +A'B'+ AB +AB' = 1 A'(B + B') + A(B +B') = 1 (since B +B' = 1) A + A' =1 1=1 proved hope it will help do same thing with second problem