Solution for question no. 1 Molarity= Moles/L Density is given, so we can use it as a conversion factor,(* = Multiply) 1.22g/1mL * 1000mL/1L * 1mol/97.19g = 12.56 mol/L = Molarity Molality = moles of solute/ kg of solvent Lets us consider 100 g of solution. Then we have 40g of solute(KSCN) g of solvent = 100g - 40g = 60g of solvent = 0.06 kg of solvent so, 12.56mol/0.06kg= 209.33mol/kg= Molality Mole fraction of KSCN= Moles of KSCN/ Sum of moles of all component Try this yourself.