Posted by: rein August 16, 2006
Login in to Rate this Post:
0
?
3=4
Proof:
Suppose:
a + b = c
This can also be written as:
4a - 3a + 4b - 3b = 4c - 3c
After reorganising:
4a + 4b - 4c = 3a + 3b - 3c
Take the constants out of the brackets:
4 * (a+b-c) = 3 * (a+b-c)
Remove the same term left and right:
4 = 3
This is wrong because u cannot divide by a+b-c which is 0 (since a+b=c)
Theorem : All numbers are equal to zero.
Proof: Suppose that a=b. Then
a = b
a^2 = ab
a^2 - b^2 = ab - b^2
(a + b)(a - b) = b(a - b)
a + b = b
a = 0
This is wrong because u cannot divide by a-b coz a-b=0 (u assumed a=b)
Theorem: 1$(dollar) = 1c(cent).
Proof:
And another that gives you a sense of
money disappearing...
1$ = 100c
= (10c)^2
= (0.1$)^2
= 0.01$
= 1c
This is wrong because (10c)^2 is not equal to (0.1$)^2
Theorem: 1 = -1 .
Proof:
1/-1 = -1/1
sqrt[ 1/-1 ] = sqrt[ -1/1 ]
sqrt[1]*sqrt[1] = sqrt[-1]*sqrt[-1]
ie 1 = -1
This is wrong because sqrt[ x/y] is not equal to sqrt[x]/sqrt[y]
Theorem: 4 = 5
Proof:
16 - 36 = 25 - 45
4^2 - 9*4 = 5^2 - 9*5
4^2 - 9*4 + 81/4 = 5^2 - 9*5 + 81/4
(4 - 9/2)^2 = (5 - 9/2)^2
4 - 9/2 = 5 - 9/2
4 = 5
This is wrong because (a-b)^2 i=(x-y)^2 doesnot mean a-b=x-y if, for example. a-b is positive and x-y is negative
0/0 = 4
0/0 = (4-4)/(2-2) = ((2+2)(2-2))/(2-2)
since 4 = 2^2 and a^2-b^2 = (a+b)(a-b)
= (2+2) = 4
Proved :)
This is wrong because u cannot 0/0 is not 1 ( as u canceled (2-2)/(2-2))