Solution to the second question de^x/dx = lim h-->0 (e^(x+h) - e^x)/h = lim h--->0 (e^x.e^h - e^x)/h = lim h--->0 {e^x(e^h -1)/h} =( e^x) lim h-->o(e^h -1)/h By the first part, lim h--->0 (e^h -1)/h = 1 Therefore, de^x/dx =( e^x) lim h-->o(e^h -1)/h = e^x.1 = e^x GOT IT??