Posted by: flip_flop June 28, 2006
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limx -> 0 ( e^ x - 1 ) / x
= limx-> 0 [ d ( e ^x - 1 ) / dx ] / [ d ( x ) / dx ]
= limx->0 e x / 1 = 1
To solve the above equation, one just need to keep L'Hopital's Rule and Derivation in mind.
Good Luck!