Posted by: ChrisCornell March 4, 2006
solve this equation
Login in to Rate this Post:     0       ?        
kasto garo... x^2 - 2^x = 0 or, x^2 = 2^x or lgx^2 = lg2^x or 2lgx = xlg2 or x/lgx = 2/lg2 therefore, x = 2; however, x/lgx = 2/lg2 can also be expressed as: (2*2)/(2*lg2) (multiplying by 2/2=1) =4/(lg2^2) = 4/lg4 Giving x = 4. Result: x = (2,4) khoi k ho k ho....hisab bhanney pachi aafu lai pisab aaucha
Read Full Discussion Thread for this article