Posted by: ChrisCornell March 4, 2006
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kasto garo...
x^2 - 2^x = 0
or, x^2 = 2^x
or lgx^2 = lg2^x
or 2lgx = xlg2
or x/lgx = 2/lg2
therefore, x = 2; however, x/lgx = 2/lg2 can also be expressed as:
(2*2)/(2*lg2) (multiplying by 2/2=1)
=4/(lg2^2)
= 4/lg4
Giving x = 4.
Result: x = (2,4)
khoi k ho k ho....hisab bhanney pachi aafu lai pisab aaucha