← Back to Kurakani

c - P R O G R A M I N G

Original Post

Write a function that receives an integer, b, that represents a number of bytes. If 1 ≤ b ≤ 8, the function will return the largest positive value that an unsigned int of b bytes can represent. If b is not in the appropriate range, the function should return -1. The function declaration is long largest(int); Assume that this function will be executed on a 64-bit operating system. You can use the pow() function which returns a double with the value b^e when called with pow(b, e). Can somebody help?

comingsoon
Sep 26, 2013 11:47 PM · 12,421 views
1 Reply
helpjava11 Sep 27, 2013 12:48 PM
Basically you need to understand the logic for this problem. 1 byte = 8 bit ( Are sure you dont mean 8 bits, bit and byte are different) You can find the largest possible integer value possible with any bit with this forlula: (2^n-1) In your case Total integer = 2^64 = 18446744073709551616 That means you can represent 0 to 18446744073709551615 with 8 bytes. #include<math.h> main() { double b = 64; b = pow(2,b); } This is not a complete code, try for yourself. If you still have doubt contact me
Login to join the conversation.

You might be interested in...

Recent Classifieds View all
Upcoming Events View all
Service Providers View all
Ask Sajha AI Assistant