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Posted on 01-16-07 9:53 AM     Reply [Subscribe]
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A doctor in Michigan has a sister who lives in California but the sister does not have any brother that lives in Michigan, how come??
:P
 
Posted on 01-18-07 7:58 PM     Reply [Subscribe]
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Brilliantly done, Republican! I admire your logic! :)

Yes, the same night I thought I solved the riddle, I asked one of my friends if she could solve it, and when trying to explain how it could be solved, I found I was mistaken myself. Yes, until third step, it works okay, then it doesn't.

Well, you did it, now I don't see the necessity of doing it another way, if there is. Also, I am still confused what is the necessity of 43L jar; any big jar just works fine, innit?

I even haven't read the other question posted by you; I will try to do it if it is interesting. :)
 
Posted on 01-18-07 8:57 PM     Reply [Subscribe]
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juggy, the containers are not full but the amount of milk in A and water in B are equal.

hetterika, you could be right : ) i'd like to see the logic behind it though, that's the interesting part, isn't it?

slackdemic, i think the 43L is just to throw you off a little.. maybe the solution would be easier if it was any other amount. Or if the question said "any big jar", you'd probably be able to find the answer sooner.
 
Posted on 01-18-07 9:22 PM     Reply [Subscribe]
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if the containers contained exaclty a cupfull of liquid, the concentration of the milk will be equal in both containers but if the volume was more than a cupfull, the concentration of the milk will be more in the container which contained milk initally when the process was started.
 
Posted on 01-18-07 9:34 PM     Reply [Subscribe]
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12 – 12 = 12 – 12
(1 + 1) (1 – 1) = (1 – 1)
(1 + 1) = 1
2 = 1
Why is it not possible?
 
Posted on 01-18-07 9:35 PM     Reply [Subscribe]
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they r not 12, 1 raised to power 2, 1^2
 
Posted on 01-18-07 9:40 PM     Reply [Subscribe]
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the concentration of milk in A would be greater because you are mixing some milk (that went from A to B, and taking a part of it back to A) to a lower amount in A.

so what i think is if you are talking about the amount, it would be tha same as in your question but if it is to do with the concentration, there would be a difference (the other way round in your question).

just a try hai.
 
Posted on 01-18-07 9:43 PM     Reply [Subscribe]
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ritthe
in your third line, you cannot have 1 on your RHS
 
Posted on 01-18-07 9:48 PM     Reply [Subscribe]
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ratamakai,

(1 - 1) in both sides cancel each other thats why 1 there.
 
Posted on 01-18-07 9:49 PM     Reply [Subscribe]
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Doctor in Michigan has a sister in california, sister means nurse. But the sister has no brother. Doctor is not her brother. Simple.
 
Posted on 01-18-07 9:52 PM     Reply [Subscribe]
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no (1-1) is 0 and you cannot cancel two zeros,
a zero canceled (or divided lets say) by another zero is never 1
 
Posted on 01-18-07 9:54 PM     Reply [Subscribe]
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yes you got it ratamakai.
 
Posted on 01-18-07 9:57 PM     Reply [Subscribe]
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substitute (1-1) by a, Then

(1+1)a = a

(1+1) = 1

2 = 1

Can be solved.......but the question itself is 0 = 0.
 
Posted on 01-18-07 10:11 PM     Reply [Subscribe]
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You can't write (1-1) for 1^2. It should be 2-1.
 
Posted on 01-18-07 10:17 PM     Reply [Subscribe]
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(1^2 - 1^2) = 1 - 1
I don't see any mistakes slackdemic, 1^2 = 1 rt?
 
Posted on 01-18-07 10:23 PM     Reply [Subscribe]
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Okay,

1^2 - 1^2 = 1^2 - 1^2

(1-1) = (1-1)

Now, how the heck did you get (1+1) on LHS..........???
 
Posted on 01-18-07 10:25 PM     Reply [Subscribe]
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This had been quite a story when I was in class 8. It took me quite a while to know where something was wrong. In case you wanted to refresh yourself with class 7-8 mathematics.

Q. Prove 2=3.

Sol. -6 = -6
=> 4 - 10 = 9 - 15
=> 4 - 10 + 25/4 = 9 - 15 + 25/4
=> 2^2 - 2x2x(5/2) + (5/2)^2 = 3^2 - 2x3x(5/2) + (5/2)^2
=> (2 - 5/2)^2 = (3 - 5/2)^2
=> 2 - 5/2 = 3 - 5/2
=> 2 = 3 //Proved//

:-)
 
Posted on 01-18-07 10:26 PM     Reply [Subscribe]
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a^2 - b^2 = (a + b) (a - b)
from formula ....... nuke
 
Posted on 01-18-07 10:38 PM     Reply [Subscribe]
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can u take square root of negative number ??? doesn't it become imaginary number ? I have never seen this one, i had seen yhe one I posted in school days. If I am wrong what is the answer galaab? Good one.
 
Posted on 01-18-07 10:39 PM     Reply [Subscribe]
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There are three people and they are blindfolded. Now, the are given one cap each, two red caps and one black cap, which they wear, unware what color it is. However, they are told that either they have a black cap or a red cap and they can see two other's cap once the blindfold is removed. Also, they are told that once the blindfold is removed, and if they see any red cap, they will have raise their hand.

Now they open their eyes. One can't see what one is wearing, but can see two other's cap. One of the people their would be able to tell "I am wearing red cap!" logically. How?
 
Posted on 01-18-07 10:40 PM     Reply [Subscribe]
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Here it is wrong --->

(4-5)/2 = (6-5)/2

-1/2 = -1/2

1 = 1

Solved //
 



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