Namaste!!!!!
if n<100,
O(n^2) runs faster then O(nlogn)
if n>=100
O(nlogn) is better, kripaya garera yeso explain garidinu hola
thanks in advance
The link posted above should help you. If that still doesn't help, post back and will try to clarify.
if n<100, O(n^2) runs faster then O(nlogn) - should be for some value of k.
Hope it helps.
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