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ha ha ha ha sachchai funny !!!

Theorem : 3=4 Proof: Suppose: a + b = c This can also be written as: 4a - 3a + 4b - 3b = 4c - 3c After reorganising: 4a + 4b - 4c = 3a + 3b - 3c Take the constants out of the brackets: 4 * (a+b-c) = 3 * (a+b-c) Remove the same term left and right: 4 = 3 Theorem : All numbers are equal to zero. Proof: Suppose that a=b. Then a = b a^2 = ab a^2 - b^2 = ab - b^2 (a + b)(a - b) = b(a - b) a + b = b a = 0 Theorem: 1$(dollar) = 1c(cent). Proof: And another that gives you a sense of money disappearing... 1$ = 100c = (10c)^2 = (0.1$)^2 = 0.01$ = 1c Theorem: 1 = -1 . Proof: 1/-1 = -1/1 sqrt[ 1/-1 ] = sqrt[ -1/1 ] sqrt[1]*sqrt[1] = sqrt[-1]*sqrt[-1] ie 1 = -1 Theorem: 4 = 5 Proof: 16 - 36 = 25 - 45 4^2 - 9*4 = 5^2 - 9*5 4^2 - 9*4 + 81/4 = 5^2 - 9*5 + 81/4 (4 - 9/2)^2 = (5 - 9/2)^2 4 - 9/2 = 5 - 9/2 4 = 5 hehe provin some theorem... challenge ur professors :)

Theorem 0/0 = 4 0/0 = (4-4)/(2-2) = ((2+2)(2-2))/(2-2) since 4 = 2^2 and a^2-b^2 = (a+b)(a-b) = (2+2) = 4 Proved :)

jhyap your logic of 3=4 is wrong. because from the question it is given a+b= c i.e a+b-c=0 while solving the equation you did (a+b-c)/(a+b-c) =1 which is wrong . as 0 divide by 0 can never be equal to 1. while making the eqaution you can never give such equations as it is against the rule of algebra.

3=4 Proof: Suppose: a + b = c This can also be written as: 4a - 3a + 4b - 3b = 4c - 3c After reorganising: 4a + 4b - 4c = 3a + 3b - 3c Take the constants out of the brackets: 4 * (a+b-c) = 3 * (a+b-c) Remove the same term left and right: 4 = 3 This is wrong because u cannot divide by a+b-c which is 0 (since a+b=c) Theorem : All numbers are equal to zero. Proof: Suppose that a=b. Then a = b a^2 = ab a^2 - b^2 = ab - b^2 (a + b)(a - b) = b(a - b) a + b = b a = 0 This is wrong because u cannot divide by a-b coz a-b=0 (u assumed a=b) Theorem: 1$(dollar) = 1c(cent). Proof: And another that gives you a sense of money disappearing... 1$ = 100c = (10c)^2 = (0.1$)^2 = 0.01$ = 1c This is wrong because (10c)^2 is not equal to (0.1$)^2 Theorem: 1 = -1 . Proof: 1/-1 = -1/1 sqrt[ 1/-1 ] = sqrt[ -1/1 ] sqrt[1]*sqrt[1] = sqrt[-1]*sqrt[-1] ie 1 = -1 This is wrong because sqrt[ x/y] is not equal to sqrt[x]/sqrt[y] Theorem: 4 = 5 Proof: 16 - 36 = 25 - 45 4^2 - 9*4 = 5^2 - 9*5 4^2 - 9*4 + 81/4 = 5^2 - 9*5 + 81/4 (4 - 9/2)^2 = (5 - 9/2)^2 4 - 9/2 = 5 - 9/2 4 = 5 This is wrong because (a-b)^2 i=(x-y)^2 doesnot mean a-b=x-y if, for example. a-b is positive and x-y is negative 0/0 = 4 0/0 = (4-4)/(2-2) = ((2+2)(2-2))/(2-2) since 4 = 2^2 and a^2-b^2 = (a+b)(a-b) = (2+2) = 4 Proved :) This is wrong because u cannot 0/0 is not 1 ( as u canceled (2-2)/(2-2))

oops , read last line as This is wrong because 0/0 is not 1 (as u canceled (2-2)/(2-2))

Jhyap, very funny. Keep it coming. You must be smoking/drinking some good stuff :) Rein, brilliant. now i know that math can be deceitful

Jhyap on Theorem: 1$(dollar) = 1c(cent). Proof: And another that gives you a sense of money disappearing... 1$ = 100c = (10c)^2 <<<<<<<<<<<<<<<<< FLAW>>>(10c)^2 = 100c^2 != 100c = (0.1$)^2 = 0.01$ = 1c <<<<<<<<<<<>>>>>>> 2*4*9/2 =72/2 !=81/2 4 - 9/2 = 5 - 9/2 4 = 5 <<<<<<<<<<<<<<<<<<