chemistry goes tougher

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 1.  calculate the ratio of concentration of 2-ethylbenzonate ion to the concentration of 2-ethylbenzoic acid at? a pH of 5.90. Ka=4.0E-5 2.  calculate the ratio of concentration of hexanoate ion to the concentration of hexanoic acid at? a pH of 6.09. Ka=41.3E-5

blackheaven123 · Jan 21, 2012 2:32 AM · 17,313 views

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So you keep posting your homeworks here and have others solve it. You will go far, specially since you don't even thank the people who solve your problems for you (check your last thread). Am I right to be annoyed with these kind of postings?

Kiddo · Jan 21, 2012 11:50 AM

Ask ur instructor

resham32 · Jan 21, 2012 8:43 PM

Even though I am not a chemistry major and have taken only general chemsitry, these are the some of the easiest problem realted to pH. Sove it using the :Henderson–Hasselbalch equation. If you don't know that that is: http://en.wikipedia.org/wiki/H... pH is given, ka is given, calculate pka and slove for the ratio of base/acid. 

tenacious · Jan 22, 2012 8:06 PM

i know the answer but don't wanna use my brain sorry

intelligentguy · Jan 22, 2012 8:21 PM

This is the easiest chemistry problem, just use HH equation 1.PH=Pka +log(B/A)  , B is the concentration of benzonate and A is the concentration of benzoic acid. 5.9=-logKa + Log(B/A) 5.9= 4.398  + log(B/A) logB/A=1.502 B/A = 31.768 2. PH=Pka +log(B/A) , B is the concentration of hexonate ion and A is the concentration of hexanoic acid 6.09  = 4.384 + log(B/A) Log (B/A) = 1.706 B/A = 50.815 make sure the calculation is right in case..

bhustigre · Jan 23, 2012 10:33 AM

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