I think you need to clarrify a bit. You are writing a hashfunction but you want the size of the hastable?  Well i dont think, first of all, you should have same funtion for both hash function and hastable.  Getting character ascii value should be easy and one googling away. So, I am trying to understand if there is more than what I understood.

Maverick · Feb 5, 2011 4:21 PM

Hi Maverick, In order to hash for a string, I would like to add the ASCII values of all the characters in that string and call it a SUM. Then I would like to have SUM % Table_Size. Let Table size be 1024 for example. The Function prototype is : int hash(char *name) {     } where *name is the pointer to the address of string.

nepal_123 · Feb 5, 2011 4:44 PM

how abt something like below, havent compiled, dont have a compiler :) This should  return the sum of the ascii values. int hash(char *name) {     int sum = 0;     int i;     for (i = 0; i < strlen(name); i++)     {          sum  = sum + name[i];        }     return sum;   }

prankster · Feb 5, 2011 8:17 PM

found an online compiler, dont know how long this link is valid http://codepad.org/xNaHQtR5 This is what it returned me ascii for A = 65 Link: http://codepad.org/xNaHQtR5&nb... code | output | fork ] Save this paste  Delete this paste C, pasted 2 minutes ago:  1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 int hash(char *name) { int sum = 0; int i; for (i=0; i < strlen(name); i++) { sum = sum + name[i]; } return sum; } int main() { int test = hash("AA"); printf("%d", test); return 0; } Output: 1 130 happy coding..

prankster · Feb 5, 2011 8:19 PM

I think he is trying to create a most simple version of a Hash Table, where sum of ascii values of a string is the hash code. And to get the index in the hash table, he needs to mod the sum by the table size: prankster bro ko solution should be: return sum%HASH_TABLE_SIZE; // Given that HASH_TABLE_SIZE is a const defined somewhere in the code

nepalithitho · Feb 5, 2011 8:26 PM

thats right nepalithito, just wanted to let him know how he can get the sum, the mod should be simple like you've given

prankster · Feb 5, 2011 8:30 PM