@ comingsoon, - hope this helps ... Proof for the Power Rule loga xn = nloga x Proof: Step 1:  Let m = loga x Step 2: Write in exponent form  x = am Step 3: Raise both sides to the power of n xn = ( am )n Step 4: Take log a of both sides and evaluate  log a xn = log a amn log a xn = mn log a a log a xn = mn log a xn = n loga x SOURCE: http://www.onlinemathlearning.... Even a video on this 1:  Last edited: 27-Oct-10 09:23 PM

black_panther · Oct 27, 2010 9:23 PM

umm! thanks Black Panther .. ...... appreciated .

comingsoon · Oct 27, 2010 10:02 PM

Not sure if this is the way to solve , however trying is not bad.     logbMr=rlogbM logbMr=logb  (M1+M2+M3...+Mr)   //m1,m2,m3 =M ; 1,2,3 represents index           =logbM1+logbM2+logbM3+....logbMr M1, M2, M3 ..Mr represents same variable M there fore the next step is just arithmetic addition, i.e addition of r variable =rx      =rlogbM      

default061 · Oct 28, 2010 10:34 AM

@Black_Panther, Did you only copy paste the solution? How would it be: log a xn = log a amn log a xn = mn log a a Without actually prooving loga xn = nloga x ? It is using the same thing which was actually asked to prove.

Khairey · Oct 28, 2010 2:55 PM

@Khairey, - i knew someone would point that out ... sooner or later ...  - i think the proof in the VDO does a better job ... 

black_panther · Oct 28, 2010 3:45 PM

  Last edited: 28-Oct-10 09:23 PM

hundari · Oct 28, 2010 9:21 PM

logbMr=logb  (M1+M2+M3...+Mr)   //m1,m2,m3 =M ; 1,2,3 represents index   was supposed to be   logbMr=logb  (M1.M2.M3....Mr)   //m1,m2,m3 =M ; 1,2,3 represents index      

default061 · Oct 29, 2010 2:33 AM