derivatives - math problem help

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find the derivative of: f(x)=ln(x+5)^(1/2)

redlotus · Mar 20, 2010 1:10 PM · 12,590 views

11 Replies

1/2(x+5) shud be the answer... (however, please confirm yourself) dlnx/dx = 1/x, so use chain rule as shown below, dln(sqrt(x+5))        d(sqrt(x+5))     __________ * ___________ d(sqrt(x+5))              dx

wtf · Mar 20, 2010 1:24 PM

in fact, i shuda been clearer.... 1/ (2(x+5)) <--- answer

wtf · Mar 20, 2010 1:25 PM

I think it should be (just thinking, but I would have this answer if I were asked) 1/2(x+5)-1/2 I haven't taken much of calculus and my familiarity with it is from my 11th grade where I passed maths by securing 36 in final exam :)  So, don't rely on it completely, though i believe in my solution to my knowledge, better check it by urself.

Namaskaar · Mar 20, 2010 1:38 PM

i think WTF is  correct.. i got the same answer..

sports freak · Mar 20, 2010 5:53 PM

Hey redlotus, when u find out correct solution, will you report it here. because as far as I know d ln(x+5)1/2 / dx = 1/2 (x+5)1-1/2 = .5(x+5)-1/2

Namaskaar · Mar 20, 2010 6:17 PM

hey namaskar , u better take some derivative classes!! i think u know nothing abt calculus and esp derivative....

sports freak · Mar 20, 2010 6:30 PM

Sports freak, I'm happy that I don't need to. Days of school overrrrrrrrrr for now. Thanx for pointing out anyway. Ya I find something wrong with my solution If the derivative was with respect to (x+5) i think my earlier solution would be right. d ln(x+5)1/2 / d (x+5) = .5 (x+5)- .5 but with respect to x only nooooooo. Sorry for giving wrong solution. My baddddddddd     :)

Namaskaar · Mar 20, 2010 6:41 PM

let me guess another soln how about 2(sqrt X) Pls someone post a real soln. I am getting curious  :) and it is boring that all other threads today in Sajha are related to dead person.

Namaskaar · Mar 20, 2010 6:47 PM

Hide steps

raju161 · Mar 20, 2010 7:11 PM

Last edited: 20-Mar-10 07:19 PM

raju161 · Mar 20, 2010 7:13 PM

Thanx raju for making it clear. Glad don't have to go thru this again :)

Namaskaar · Mar 20, 2010 9:52 PM

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