Your dimensions are right. (A-A1) is a 4x4 matrix and B1 is a 4x2 matrix which implies your Am matrix is 2x4.  I just tried it in matlab. Type this in your program or command window after defining the matrices A, B1, A1; Am=B1\(A-A1); remember it's \ not / However, Am is coming out to be a zero matrix. I don't know if that is right. Solution from matlab: A =          0    1.0000         0   -0.0001     7.5781   21.2169   -2.4152   -6.1767          0   -0.0004         0    1.0001    27.2402   78.6220   -8.6725  -22.9705 A1 =          0    1.0000         0         0     7.5781   21.2169   -2.4152   -6.1767          0         0         0    1.0000    27.2402   78.6220   -8.6725  -22.9705 B1 =          0         0     1.0000    0.0022          0         0          0    1.0000 Am =      0     0     0     0      0     0     0     0

santosh1984 · Dec 6, 2009 11:31 PM

Thank you Santosh.It was great help.

birajasharma · Dec 7, 2009 1:59 AM

Keep it up guys, it's a good thread. Jaach ma chai malai yeso dekhau hai......bro haru

truthspeaker · Dec 7, 2009 4:00 AM

cheers for the guy like santosh 1984.. guys like you are new hope for sajha.....Nepal ta kaaataam bhayooo ghou....

bostonktm · Dec 7, 2009 2:44 PM

If Am = 0 then A = A1. Clearly that is not true. Look at A(2,3) = -0.0004 and A1(2,3) = 0.Small difference, I suppose. I wonder if this is more subtle?

GuitarDaku · Dec 7, 2009 3:59 PM