Posted by: ANS March 2, 2011
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Is this correct ??
the point is (3, 3 2/3).................. [³√3²=3 2/3]
Now for slope m,
dy/dx=d(x2/3)/dx= 2/3 x-1/3
at poin x=3
2* 3 -1/3/3= 2*(3 -1/3* 3 -1) = 2*3 -4/3
The line is perpendicular is m=-2-1*3 4/3
finally the equation of the normal line is
y-32/3=-2-1*3 4/3(x-3)
y = -2-1*3 4/3 x + 2-1*32/3 +2-1*3 7/3
OR
y=(-3 4/3/2 )x +3 2/3 +3 7/3/2