Posted by: Khairey October 28, 2010
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@Black_Panther, Did you only copy paste the solution?
How would it be:
log a xn = log a amn
log a xn = mn log a a
Without actually prooving loga xn = nloga x ? It is using the same thing which was actually asked to prove.
How would it be:
log a xn = log a amn
log a xn = mn log a a
Without actually prooving loga xn = nloga x ? It is using the same thing which was actually asked to prove.