Posted by: Guest4 September 24, 2007
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Perrybhadra is right, but if it helps you understand better, here is another way:
P(not A and not B)
=1- P (A union B)
= 1 - [ P(A) + P(B) - P(A and B)
= 1- P(A) -A(B) + P(A)P(B) (if A and B are independent)
*you should get the same answer both ways.