Posted by: RajaHarischandra June 29, 2006
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Solution to the second question
de^x/dx = lim h-->0 (e^(x+h) - e^x)/h
= lim h--->0 (e^x.e^h - e^x)/h = lim h--->0 {e^x(e^h -1)/h}
=( e^x) lim h-->o(e^h -1)/h
By the first part, lim h--->0 (e^h -1)/h = 1
Therefore, de^x/dx =( e^x) lim h-->o(e^h -1)/h = e^x.1 = e^x
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