Posted by: hyakula March 3, 2006
solve this equation
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How about this?? x^2-2^x=0 x^2=2^x log (x^2) = log (2^x) 2 log x = x log 2 log x / x = log 2 / 2 log x ^(1/x) = log 2 ^(1/2) This is true only if x = 2
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