uff how to prove this?
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@ comingsoon,
- hope this helps ...
Proof for the Power Rule
loga xn = nloga x
Proof:
Step 1:
Let m = loga x
Step 2: Write in exponent form
x = am
Step 3: Raise both sides to the power of n
xn = ( am )n
Step 4: Take log a of both sides and evaluate
log a xn = log a amn
log a xn = mn log a a
log a xn = mn
log a xn = n loga x
SOURCE:
http://www.onlinemathlearning.com/logarithms-properties.html
Even a video on this 1: 
Last edited: 27-Oct-10 09:23 PM
@Black_Panther, Did you only copy paste the solution?
How would it be:
log a xn = log a amn
log a xn = mn log a a
Without actually prooving loga xn = nloga x ? It is using the same thing which was actually asked to prove.
How would it be:
log a xn = log a amn
log a xn = mn log a a
Without actually prooving loga xn = nloga x ? It is using the same thing which was actually asked to prove.
@Khairey,
- i knew someone would point that out ... sooner or later ... 
- i think the proof in the VDO does a better job ...
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